SGU171 解题手记
  贪心。将所有的学生按weight从大到小排序,然后按顺序让每个人去刚好能去的zone(即没邀请满人的zone中level刚好小于这个学生的),如果没地方可去,就暂时记为“无处可去”。最后,把所有“无处可去”的学生随意分配到没满的zone。
  Submit 1: AC。

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#include <cstdio>
#include <algorithm>
using namespace std;
 
struct student
{
    int id,level,weight;
};
 
bool operator <(const student &a,const student &b)
{
    return a.weight>b.weight;
}
 
struct zone
{
    int id,level,cap;
};
 
bool operator <(const zone &a,const zone &b)
{
    return a.level>b.level;
}
 
bool operator <(int level,const zone &a)
{
    return a.level<level;
}
 
int main()
{
    student students[16000];
    zone zones[100];
    int invite[16001];
    int k,n=0;
    scanf("%d",&k);
    for (int i=0;i<k;i++)
    {
        scanf("%d",&zones[i].cap);
        zones[i].id=i+1; n+=zones[i].cap;
    }
    for (int i=0;i<k;i++)
        scanf("%d",&zones[i].level);
    for (int i=0;i<n;i++)
    {
        scanf("%d",&students[i].level);
        students[i].id=i+1;
    }
    for (int i=0;i<n;i++)
        scanf("%d",&students[i].weight);
    sort(zones,zones+k);
    sort(students,students+n);
    for (int i=0;i<n;i++)
    {
        zone *p=upper_bound(zones,zones+k,students[i].level);
        while (p-zones<k && p->cap==0) p++;
        if (p-zones<k)
        {
            invite[students[i].id]=p->id;
            p->cap--;
        }
        else invite[students[i].id]=-1;
    }
    for (int i=1,firstzone=0;i<=n;i++)
    {
        if (invite[i]==-1)
            for (int j=firstzone;j<k;j++) if (zones[j].cap)
            {
                invite[i]=zones[j].id; zones[j].cap--; firstzone=j; break;
            }
        printf("%d ",invite[i]);
    }
    return 0;
}